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What is the equation of the line that contains the two points (0, ) and (, )?
0,-1 -1, -3
@iGreen
First, find the slope. \(m = \dfrac{y_2-y_1}{x_2-x_1}\) \(m = \dfrac{-3+1}{-1-0}\) Can you finish that? @ispike
so 2
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Yep.
So the slope is 2.
is there more ? i feel like there is
Now we can plug that and one of the points into point-slope form. \(y - y_1 = m(x - x_1)\) Where \(m\) is the slope, \(y_1\) is the y-value, and \(x_1\) is the x-value. We can use the point (0, -1). \(y + 1 = 2(x - 0)\) Simplify: \(y + 1 = 2(x)\) Multiply: \(y + 1 = 2x\) Subtract 1 to both sides, what do you get? @ispike
y=2x-1?
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Yep, so that's your answer.
That's your equation.. y = 2x - 1.
thank you
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