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Mathematics 13 Online
OpenStudy (twizttiez):

1.The height of a ball when it is thrown into the air is shown by equation h = −16t2 + 20t + 3, where h is the height of the ball and t is time in seconds since the ball was released. 2.A salesperson’s monthly earnings are shown by the equation e = 1200 + 0.04s, where e represents the salesperson’s monthly earnings and s is her monthly sales 3.The amount of a 500 g sample of a radioactive substance that remains over time is given by the equation , where d is the number of days since the sample weight was 500 g. 4.Mikaela’s distance from home as she drives at a constant rate is given by

OpenStudy (twizttiez):

I need help @Jhannybean i think 1 is non linear 2 is linear 3 is non linear and 4 is linear

OpenStudy (jhannybean):

nonlinears are quadratics.

OpenStudy (jhannybean):

Not sure about 2

OpenStudy (twizttiez):

Well how can i determine whether or not they are quadratics?

OpenStudy (twizttiez):

So 2 isn't linear

OpenStudy (jhannybean):

3 looks like it's some kind of exponential growth function.

OpenStudy (twizttiez):

4. Mikaela’s distance from home as she drives at a constant rate is given by the equation d = 368 – 42t, where d is her distance from home and t is time in hours.

OpenStudy (twizttiez):

Thats the full version of 4

OpenStudy (jhannybean):

4 I think woud be linear. Think about her going a certain distance at a constant rate,

OpenStudy (twizttiez):

So i was right about 4?

OpenStudy (jhannybean):

You'd calculate her time by point A, her home, to point B, distance from home.

OpenStudy (jhannybean):

Yes.

OpenStudy (jhannybean):

Fix 2 and 3 though. Google exponential growth function examples, you'll get an idea.

OpenStudy (jhannybean):

for number 3 I mean.

OpenStudy (twizttiez):

Ok so so far i have 1 as non linear 2 linear 3 nonlinear and 4 as linear does that sound right?

OpenStudy (jhannybean):

Gotta go, good luck.

OpenStudy (twizttiez):

Oh bye

OpenStudy (jhannybean):

Hm, graphed 2 and it appeared to be linear. I guess you were right about that.

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