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OpenStudy (anonymous):
Verify the identity
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OpenStudy (anonymous):
OpenStudy (anonymous):
I know I would start by combining the fractions on the left right?
OpenStudy (isaiah.feynman):
Yes. Do that.
OpenStudy (anonymous):
I can help you. just a sec. I need to solve it
OpenStudy (anonymous):
Okay thank you so much
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OpenStudy (isaiah.feynman):
@dtuniyants We're actually meant to tutor a person to the solution, and not solve a problem and spoon feed them the answer. :P
OpenStudy (anonymous):
first, write the left part of identity as one fraction\[((\cos^2x)+(1+sinx)^2)/((1+sinx)*cosx)\]
OpenStudy (anonymous):
@Isaiah.Feynman I'm solving and tutoring the person to solution. Don't say things before you are sure that it is so!
OpenStudy (anonymous):
So to combine the two fractions, we would literally just be putting them together? And then we simplify?
OpenStudy (anonymous):
After that use FOIL to reduce parathenthles:
Yes we need to simplify\[(\cos^2x+\sin^2x+2sinx+1)/((sinx+1)*cosx)\]
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OpenStudy (isaiah.feynman):
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