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What is the value of integral 0 to 4 3x^2 sqrt (x^3 + 1) dx?
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well, what do you think you can do?
That's sort of why I'm on here...to get a little help.
Hint\[ \int_0^4 3x^2\sqrt{x^3+1}~dx = \int_0^4\sqrt{x^2+1}~d(x^3+1) \]
well u=x^3+1
u = x^3+1, so your du is going to be equal to dx times the derivative of u.
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so, what happens if you do a substitution?
like the one solomon suggested
Ok so du = dx(3x^2), right?
yes du=3x^2 dx
yep, so now, can you integrate your remaining function?
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