Question

Prove (sec x - tan x)^2 = (1-sin x)/1+sin x

Answer 1

I distribute the square of 2 first right?

Answer 2

I would think so... yes.

Answer 3

1 - sin ^2 x = cos ^2 x?

Answer 4

what is this for here, right now?

Answer 5

what you mean?

Answer 6

oh

Answer 7

no, they are not squared, my bad...

Answer 8

do you still need help

Answer 9

yes, just distribute the power of 2....

Answer 10

then i get \[\frac{ 1 }{ \cos^2 x } - \frac{ \sin^2 x}{ \cos^2 x}\]

Answer 11

thats after simplfying from sec^2 x - tan ^2 x

Answer 12

I don't see a need in doing it NOW.