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Simplify to lowest terms, if possible: (12 z^2)/(16 z^4)
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can you reduce the fraction \[\frac{12}{16}\]?
what about the exponents? @satellite73
we'll get there one step at a time
3/4
ok good now how about \[\frac{z^2}{z^4}\]?
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would you subtract them?
yes you subtract the exponents, but since 4 is larger than 2, i would subtract with the z in the denominator
\[\frac{12z^2}{16z^4}=\frac{3}{4z^{4-2}}=\frac{3}{4z^2}\]
you are really just cancelling \[\frac{z^2}{z^4}=\frac{z\times z}{z\times z\times z\times z}=\frac{1}{z\times z}=\frac{1}{z^2}\]
got it thanks!!
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yw
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