Mathematics
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OpenStudy (anonymous):
I have to graph this polynomial
f(x)=x^3-4x+1
Where do I start?
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OpenStudy (hunus):
Do you know what x^3 looks like?
OpenStudy (anonymous):
yes, like if I put in a 1, x is still 1. If I put in a 2, x is 8
OpenStudy (hunus):
Let's start with x=0
OpenStudy (hunus):
\[f(0)=0^3 - 4*0 + 1 = 1\]
OpenStudy (hunus):
You're having to actually graph this, right?
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OpenStudy (anonymous):
Yes
OpenStudy (hunus):
Do you know to what x-values are you having to graph it?
OpenStudy (anonymous):
So, with x=0, y just =-3, right?
OpenStudy (hunus):
With x=0, y=1
OpenStudy (hunus):
because zero cubed is zero and four times zero is still zero.
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OpenStudy (anonymous):
Oh my goodness :/ I was adding it and driving myself nuts, I'm good, thanks:)
OpenStudy (anonymous):
I've been doing toooo much homework sorry
OpenStudy (hunus):
You're fine lol
OpenStudy (hunus):
You still need help with this one?
OpenStudy (anonymous):
No, I can get my five points now and make my graph. Thanks.
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OpenStudy (anonymous):
(0, 1) (1,3)(-1,4)(2,1)(-2,1)?
no
OpenStudy (hunus):
For x = 1
1^3 - 4*1 + 1 = 1 - 4 + 1 = -2
OpenStudy (hunus):
(0, 1)
(1, -2)
OpenStudy (anonymous):
Thanks
OpenStudy (hunus):
Yup