Eliminate the parameter. x = t + 4, y = t^2
we can 'eliminate' the parameter t by algebra x -4 = t now substitute into y
So it becomes x = -4 + 4 and y = -4^2? @perl
The answers are: y = √x + x + 4 y = √x - 4 y = x^2 + 16 y = x^2 - 8x + 16 I chose y = x^2 + 16 as the answer. Is that right? @AnswerMyQuestions @perl @iGreen
@brainbuzzed5646 @TheSmartOne @rose18920 any help?
sorry @sunshine201 math is not my best subject.... i don't want to give you a wrong answer but if no one else answers you back you should just go with your own answer :)
Okay :) thank you anyway.
we can 'eliminate' the parameter t by algebra first solve for t x -4 = t now substitute into y = t^2 y = (x-4)^2
now you can expand that
So the answer would be y = x^2 - 8x + 16?
@perl
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