Solve the proportion. Picture included...Totally lost.

Question

anonymous · Answer

attachment

anonymous · Answer

hey is that ur real pic

anonymous · Answer

SO far I've got that I rearrange it to 2(0.5z^2 + 7) = z(z-5). But IDK what to do afterwards.

anonymous · Answer

@Carpenter12 No, that's Ariana Grande.

anonymous · Answer

i knew it looked too filmier

anonymous · Answer

Hahaha, yeah.

anonymous · Answer

@AriPotta Can you possibly help me?

nikato · Answer

Do you know how to distribute?

anonymous · Answer

Um, kind of. Am I supposed to distribute in this? O.o

nikato · Answer

Yes. Distribute on both sides.

Remember it's like this
a(b+c)= ab+ac

anonymous · Answer

ohh. So I distribute the 2?

nikato · Answer

Yea

anonymous · Answer

|dw:1417744885959:dw| Like this?

nikato · Answer

Correct

anonymous · Answer

So then it would just because 0.5z^2 + 14 = z(z-5)? DO I distribute the z too?

nikato · Answer

Wait, what's 2x0.5?

And yes, you distribute the z too

anonymous · Answer

Does the 0.5z^2 cancel out and make it 14 - -5z?

It's not 2x0.5 it's saying 0.5z to the 2nd power, btw.

anonymous · Answer

14 = -5z ** not 14 - - 5z

nikato · Answer

I know. But it's wrong. 

2(0.5z^2)
And using associative property
(2x0.5)z^2
= z^2

anonymous · Answer

ohh..so then it becomes z^2 + 14 = z^2 - 5z? and THEN 14 = -5z ?

nikato · Answer

Correct.
Now divide both sides by -5 to solve for z

anonymous · Answer

ohhh. I got it now.