Mathematics
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OpenStudy (anonymous):
will fan and medal for homework help!
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OpenStudy (anonymous):
Solve each equation using the quadratic formula.
OpenStudy (anonymous):
x^2+8x+12=0
OpenStudy (anonymous):
Do you know what the quadratic formula is?
OpenStudy (anonymous):
yes, i do
OpenStudy (anonymous):
-b (plus or minus) square root b^2-4ac over 2a
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OpenStudy (anonymous):
Okay, for x^2+8x+12=0, what is a, b and c?
OpenStudy (anonymous):
Exactly!
OpenStudy (anonymous):
x= -2, -6
OpenStudy (anonymous):
a=1, b=8, c=12
OpenStudy (anonymous):
All you have to do now is plug these numbers in and simplify the fraction :)
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OpenStudy (anonymous):
go on www.mathway.com for answer.
OpenStudy (anonymous):
okay one second @tom982
OpenStudy (anonymous):
i don't have to minus 12 or anything?
OpenStudy (anonymous):
\[ x= \frac{-b \pm \sqrt{b^2-4ac}}{2a} \]So \[ x= \frac{-8 \pm \sqrt{8^2-4*1*12}}{2*1} \]
OpenStudy (anonymous):
That's all you have to simplify :)
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OpenStudy (anonymous):
...that's the answer?
OpenStudy (anonymous):
well, after simplifying it?
OpenStudy (anonymous):
yes and you will come out with 2 answers because you add and subtract the square root
OpenStudy (anonymous):
got that one :)
OpenStudy (anonymous):
can you help me with more if i make another question? i will give more medals :o
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
2x^2+5x=7
OpenStudy (anonymous):
Okay so subtract 7 from both sides to make it equal 0: 2x^2+5x-7=0. Then use a=2, b=5 and c=-7 in the formula :)
OpenStudy (anonymous):
after subtracting 7, would it turn into 2x^2+5x-7?
OpenStudy (anonymous):
@tom982
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OpenStudy (anonymous):
Yeah
OpenStudy (anonymous):
so now what?
OpenStudy (anonymous):
@tom982
OpenStudy (anonymous):
What I said before:
"Okay so subtract 7 from both sides to make it equal 0: 2x^2+5x-7=0. Then use a=2, b=5 and c=-7 in the formula :)"
OpenStudy (anonymous):
ah okay i forgot to write that it is =0 :p
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OpenStudy (anonymous):
-5+/- square root 5^-4(2)(7)
OpenStudy (anonymous):
42 times 7 = 294?
OpenStudy (anonymous):
Be careful of the double negative in the -4ac term:
\[x= \frac{-5 \pm \sqrt{5^2-4*a*(-7)}}{2*2}\]
OpenStudy (anonymous):
Oops, left an a in there, it should be 2.
OpenStudy (anonymous):
i didn't make the 7 negative before lol
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OpenStudy (anonymous):
so, -294? @tom982
OpenStudy (anonymous):
-4*2*-7=56
OpenStudy (anonymous):
i did 5 to the second power before all of that, should i not do that?
OpenStudy (anonymous):
\[x= \frac{-5 \pm \sqrt{25+56}}{4}\]
OpenStudy (anonymous):
Indices should come first, yes. But I have no idea where you're getting 294 from :p
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OpenStudy (anonymous):
5*5=25-4=21*2=42+7=294
OpenStudy (anonymous):
but you arent supposed to mess with the 5*5 i just figured out
OpenStudy (anonymous):
42*7=294 not 42+7 lol sorry
OpenStudy (anonymous):
No no, never do that!
OpenStudy (anonymous):
now i know :)
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OpenStudy (anonymous):
Great :) Can you tell me the answer now?