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Mathematics 7 Online
OpenStudy (anonymous):

will fan and medal for homework help!

OpenStudy (anonymous):

Solve each equation using the quadratic formula.

OpenStudy (anonymous):

x^2+8x+12=0

OpenStudy (anonymous):

Do you know what the quadratic formula is?

OpenStudy (anonymous):

yes, i do

OpenStudy (anonymous):

-b (plus or minus) square root b^2-4ac over 2a

OpenStudy (anonymous):

Okay, for x^2+8x+12=0, what is a, b and c?

OpenStudy (anonymous):

Exactly!

OpenStudy (anonymous):

x= -2, -6

OpenStudy (anonymous):

a=1, b=8, c=12

OpenStudy (anonymous):

All you have to do now is plug these numbers in and simplify the fraction :)

OpenStudy (anonymous):

go on www.mathway.com for answer.

OpenStudy (anonymous):

okay one second @tom982

OpenStudy (anonymous):

i don't have to minus 12 or anything?

OpenStudy (anonymous):

\[ x= \frac{-b \pm \sqrt{b^2-4ac}}{2a} \]So \[ x= \frac{-8 \pm \sqrt{8^2-4*1*12}}{2*1} \]

OpenStudy (anonymous):

That's all you have to simplify :)

OpenStudy (anonymous):

...that's the answer?

OpenStudy (anonymous):

well, after simplifying it?

OpenStudy (anonymous):

yes and you will come out with 2 answers because you add and subtract the square root

OpenStudy (anonymous):

got that one :)

OpenStudy (anonymous):

can you help me with more if i make another question? i will give more medals :o

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

2x^2+5x=7

OpenStudy (anonymous):

Okay so subtract 7 from both sides to make it equal 0: 2x^2+5x-7=0. Then use a=2, b=5 and c=-7 in the formula :)

OpenStudy (anonymous):

after subtracting 7, would it turn into 2x^2+5x-7?

OpenStudy (anonymous):

@tom982

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

so now what?

OpenStudy (anonymous):

@tom982

OpenStudy (anonymous):

What I said before: "Okay so subtract 7 from both sides to make it equal 0: 2x^2+5x-7=0. Then use a=2, b=5 and c=-7 in the formula :)"

OpenStudy (anonymous):

ah okay i forgot to write that it is =0 :p

OpenStudy (anonymous):

-5+/- square root 5^-4(2)(7)

OpenStudy (anonymous):

42 times 7 = 294?

OpenStudy (anonymous):

Be careful of the double negative in the -4ac term: \[x= \frac{-5 \pm \sqrt{5^2-4*a*(-7)}}{2*2}\]

OpenStudy (anonymous):

Oops, left an a in there, it should be 2.

OpenStudy (anonymous):

i didn't make the 7 negative before lol

OpenStudy (anonymous):

so, -294? @tom982

OpenStudy (anonymous):

-4*2*-7=56

OpenStudy (anonymous):

i did 5 to the second power before all of that, should i not do that?

OpenStudy (anonymous):

\[x= \frac{-5 \pm \sqrt{25+56}}{4}\]

OpenStudy (anonymous):

Indices should come first, yes. But I have no idea where you're getting 294 from :p

OpenStudy (anonymous):

5*5=25-4=21*2=42+7=294

OpenStudy (anonymous):

but you arent supposed to mess with the 5*5 i just figured out

OpenStudy (anonymous):

42*7=294 not 42+7 lol sorry

OpenStudy (anonymous):

No no, never do that!

OpenStudy (anonymous):

now i know :)

OpenStudy (anonymous):

Great :) Can you tell me the answer now?

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