Question

Use basic identities to simplify the expression.

\(\dfrac{cos^2\theta}{sin^2\theta}~+~csc\theta~sin\theta\)

\(csc^2\theta\)
\(sec^2\theta\)
1
\(tan^2\theta\)

Answer 1

@satellite73 @e.mccormick

Answer 2

\[ \dfrac{cos^2\theta}{sin^2\theta}~+~csc\theta~sin\theta = \dfrac{cos^2\theta}{sin^2\theta}~+~ \frac{sin(\theta)}{sin(\theta)} = cot^2(\theta)+1 = csc(\theta) \]

Answer 3

But that isn't one of the options?

Answer 4

@myininaya

Answer 5

Um, is that supposed to be csc on the right?

Answer 6

Sorry, I missed the squared off there, it should be \[csc^2(\theta)\]

Answer 7

Yah.

Answer 8

Well, there is more than one possible answer. They may have it in a different form.