Use basic identities to simplify the expression.

$\dfrac{cos^2\theta}{sin^2\theta}~+~csc\theta~sin\theta$

$csc^2\theta$
$sec^2\theta$
1
$tan^2\theta$

Question

Use basic identities to simplify the expression.

$\dfrac{cos^2\theta}{sin^2\theta}~+~csc\theta~sin\theta$

$csc^2\theta$
$sec^2\theta$
1
$tan^2\theta$

sleepyjess · Answer

@satellite73 @e.mccormick

anonymous · Answer

$$ \dfrac{cos^2\theta}{sin^2\theta}~+~csc\theta~sin\theta = \dfrac{cos^2\theta}{sin^2\theta}~+~ \frac{sin(\theta)}{sin(\theta)} = cot^2(\theta)+1 = csc(\theta) $$

sleepyjess · Answer

But that isn't one of the options?

sleepyjess · Answer

@myininaya

e.mccormick · Answer

Um, is that supposed to be csc on the right?

anonymous · Answer

Sorry, I missed the squared off there, it should be $$csc^2(\theta)$$

e.mccormick · Answer

Yah.

e.mccormick · Answer

Well, there is more than one possible answer.  They may have it in a different form.