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Factor the algebraic expression below in terms of a single trigonometric function. cos x - sin 2x - 1
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\[\cos(x)-\sin(2x)-1\] or \[\cos(x)-\sin^2(x)-1\]
@satellite73 can try my question pls
It's cos(x)-sin^2(x)-1
ok then maybe we can use \[\sin^2(x)+\cos^2(x)=1\] somewhere
replace \(\sin^2(x)\) by \(1-\cos^2(x)\) in your expression you get \[\cos(x)-(1-\cos^2(x))-1\] then some algebra to fix it up a bit
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