Write a compound inequality that represents the situation. All real numbers that are greater than -8 but less than 8. HELP? @satellite73
@cwrw238
@iGreen
@ganeshie8
A compound inequality would be \( a < x < b\)
So what will 'a' and 'b' be in this case?
a = -8? b = 8?
Not quite..it says GREATER than -8.. if you put -8 in the 'a' spot it gives you: \(-8 < x < b\) Which says that -8 is LESS THAN.
okay, so -8 would be b?
Yep, and 'a' will be?
but all of the possible answers have -8 first
Oh. Well can I see your choices?
Oh, I totally forgot that I didn't type them out already, oops. Yeah, here's the choices.
Wow, this is much easier than I thought.. \(<\) this is the less than sign. \(>\) this is the greater than sign. \(\le\) this is the less than or equal to sign. \(\ge\) this is the greater than or equal to sign. The sentence says GREATER THAN -8, but LESS THAN 8. So which one should be your answer?
That's what's confusing me is that there isn't any greater than signs and -8 is at the beginning so
I feel like it's C
but I'm hesitant to believe anything that I think is right haha
Same..it doesn't say any 'or equal to' signs..and C is the only one that doesn't have any..
Lol. Yeah, this question doesn't seem to make much sense to me.. :l I think greater than -8, but less than 8 should look like: 8 < x < -8 But I guess C is your best choice.
Thank you, it was right.
Now this question is a beast and I'm scared lol.
Ugh, sorry. I can't help you here..I'm horrible with sequences.
hahaha that's okay thanks
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