Let an integer be chosen at random from the integers 1 to 30 inclusive. Find the probability that the integer chosen is divisible by 3. 9/30 11/30 1/3
@iGreen
Um, what numbers are divisible by 3 between (and including) 1 and 30? Just find the first 10 multiples of 3.
3 * 1 = ? 3 * 2 = ? 3 * 3 = ? 3 * 4 = ? 3 * 5 = ? 3 * 6 = ? 3 * 7 = ? 3 * 8 = ? 3 * 9 = ? 3 * 10 = ?
Well, we don't even have to find them..just count how many there are.
Sorry net is moving slow, or maybe it's the site. :/ 3,6,9,12,15,18,21,24,27,30,33,36
@iGreen
Okay, count the one's between 1 and 30, how many are there? Yeah, it's Open Study's site.
11, correct?
@iGreen
No..check again.
9? I thought I was supposed to include 1 and 30.
No, 9 is wrong too..1 is not a multiple of 3.
1 is not divisible by 3*
3 * 1 = 3 3 * 2 = 6 3 * 3 = 9 3 * 4 = 12 3 * 5 = 15 3 * 6 = 18 3 * 7 = 21 3 * 8 = 24 3 * 9 = 27 3 * 10 = 30 @igreen
Yep, and how many is that?
You gave me 10 problems. Or are you talking about the 30?
Yes, 10 problems..
Since there are 10 numbers that are divisible by 3 between (and including) 1 and 30, the probability of picking a number divisible by 3 is 10/30. You can simplify 10/30, and what is that?
1/3
Yep, so that's your answer.
Thanks Green!
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