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Mathematics 7 Online
OpenStudy (secret-ninja):

Am I right?

OpenStudy (secret-ninja):

Mike packed an equal number of flashlights in each of x gift boxes. The number of compartments in each gift box was 3 more than the number of boxes. The number of flashlights in each compartment of a box was 2 more than the number of compartments in each box. The expression below shows the total number of flashlights that Mike packed in all the boxes: x(x + 3)(x + 5) Which expression shows the number of flashlights in each box? x + 3 x + 5 (x + 3)(x + 5) x(x + 3)(x + 5)

OpenStudy (secret-ninja):

I think its B.

OpenStudy (secret-ninja):

I chose A previously, but it was incorrect.

OpenStudy (anonymous):

I know this isn't an answer to your question, but if I help you can you help me? I've been asking for help for ages on one question.

OpenStudy (secret-ninja):

I saw in an old question that someone chose B and got that one wrong so I'm confused >.<

OpenStudy (secret-ninja):

I can try, though I can't guarantee I'll know it. :]

OpenStudy (anonymous):

I think the last one but, not sure

OpenStudy (anonymous):

Okay, so the number of compartments (c) is c = x + 3. The number of flashlights in each compartment (f) is f = c + 2

OpenStudy (anonymous):

This means that the number of flashlights in each compartment is f = (x + 3) + 5

OpenStudy (anonymous):

in x boxes you have, x(x+3)(x+5) in 1 box, you will have total amount / total boxes x(x+3)(x+5)/x = (x+3)(x+5)

OpenStudy (secret-ninja):

So it is D?

OpenStudy (anonymous):

So, let's say there were 3 boxes. This would mean x = 3. The number of compartments in each box would be 5, and the number of flashlights in each compartment would be 8.

OpenStudy (anonymous):

Multiply 8 by the number of compartments in each box (5) and we get 40. Plug x = 3 into each equation, and see which one comes out to 40

OpenStudy (anonymous):

wait...

OpenStudy (anonymous):

No, the number of compartments in each box would be 6, which would mean the solution would be 48

OpenStudy (anonymous):

I think the answer is C

OpenStudy (secret-ninja):

Thanks ^-^

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