Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

can someone help me? giving medal

OpenStudy (anonymous):

OpenStudy (anonymous):

plz help

OpenStudy (anonymous):

So first we need to figure out how far Felix will travel if he goes the long way. So we need to add the the two sides up. (0.7 and 2.4)

OpenStudy (anonymous):

and u get 3.1?

OpenStudy (anonymous):

plz help

OpenStudy (anonymous):

Now we need to find the hypotenuse. Do get it we should use this formula: \[a^2+b^2=c^2\] We are trying to find c. to get c we must replace a with 0.7 and b with 2.4

OpenStudy (anonymous):

So what is the new equation?

OpenStudy (anonymous):

0.7^2 + 2.4^2 = c^2?

OpenStudy (anonymous):

Yes, so to solve for c we have to squar 0.7 and 2.4 and then add them together. Are you aloud to use a calculator?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

OK so multiply 0.7 by 0.7

OpenStudy (anonymous):

0.49

OpenStudy (anonymous):

and what is 2.4 times 2.4?

OpenStudy (anonymous):

5.76

OpenStudy (anonymous):

now what?

OpenStudy (anonymous):

now add 0.49 to 5.76

OpenStudy (anonymous):

i got 6.25

OpenStudy (anonymous):

ok so \[6.25=c^2\]

OpenStudy (anonymous):

do you know how i got that?

OpenStudy (anonymous):

6.25*6.25??

OpenStudy (anonymous):

no, what we did was use the formula \[a^2+b^2=c^2\] and then we plugged in the length of the sides of the rectangle for a and b. then we did the math by squaring the two lengths and adding them together. the next step is to find the square root of 6.25

OpenStudy (anonymous):

oh ok i got confused

OpenStudy (anonymous):

the square root of 6.25 is 2.5?

OpenStudy (anonymous):

Yes that is correct. That is the distance of if Felix were to travel diagonally across the park. So now all we have to do is subtract 2.5 from 3.1\[3.1-2.5\]

OpenStudy (anonymous):

that will be your final answer. :D

OpenStudy (anonymous):

0.6 is that right?

OpenStudy (anonymous):

Yup. That is the answer to the question "How much farther would Felix travel..." ect

OpenStudy (anonymous):

thank you! :D

OpenStudy (anonymous):

No problem :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!