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What value of k solves the equation?
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did you learn logarithms yet?
No
okay, then another way to do this is to know that anything to a negative exponent makes it a reciprocal. so the question is basically 1/k^5 = 1/32. So, what goes into 32 five times is k. in this case, it's 2. so 2^-5=1/32.
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\[ \sqrt[5]{1/32}\]= k is another way to write it. you'll get 1/2, but remember, that since it's a negative exponent, it would be 1/2 to the power of -1. then the reciprocal is 2, the answer is k=2.
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What value of c solves the equation?
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