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Mathematics 47 Online
OpenStudy (dj3strella):

help me @nikato

OpenStudy (dj3strella):

i think its a rectangle

OpenStudy (triciaal):

I think rhombus

OpenStudy (nikato):

i think rectnangle is correct

OpenStudy (triciaal):

in order to be a rectangle then all right angles perpendicular at end parallelogram is a rectangle out of shape rhombus is a square out of shape

OpenStudy (nikato):

CANT be rhombus because the diagonlas wont always be congrunet.

OpenStudy (triciaal):

square and rhombus lengths the same

OpenStudy (nikato):

the only proporty of the diagnolas of a rhombus is that they are perpendicular

OpenStudy (nikato):

because a property of the diagonals of a rectanlge is that they are congrunet. and a square IS a special rectnangle

OpenStudy (triciaal):

"A parallelogram is a rhombus if and only if its diagonals are perpendicular A parallelogram is a rhombus if and only if each diagonal bisects a pair of opposite angles A parallelogram is a rectangle if and only if its diagonals are congruent."

OpenStudy (dj3strella):

so its a rectangle?

OpenStudy (nikato):

^exactly so according to our only given info "congruent diagonals" the paraleelogram is a rectangle. we dont know if the diagnolas bisect each otger or whether they are perpendicular and yes. i believe its a rectangle

OpenStudy (triciaal):

based on theorem 6.13 yes this would be a rectangle

OpenStudy (triciaal):

the diagram looks like a rhombus, the diagonals still look perpendicular but the question states specifically that the diagonals are congruent therefore rectangle

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