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Solve for the tension T in the vertical section of string. Express T in terms of the known variables I, m, r, and g
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I*alpha = -Tr Tr = -I*alpha T = -I*alpha/r Omega = v/r you can derive alpha = a_y/r T = -I*alpha/r T = -I*(a_y/r)/r = -I*a_y/r^2 ma_y = T - mg ma_y = -I*a_y/r^2 - mg ma_y + I*a_y/r^2 = -mg Distributive law a_y(m + I/r^2) = -mg a_y = -mg / (m + I/r^2)
PS: you should go in the physics section
so the answer is T=-I(-mg/m+1/r^2)/r^2 ???
no the very last one ii wrote
a_y = -mg / (m + I/r^2) this is the answer?
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id say so but remember it's what T is
a_y is what was used to explain it
so T=-mg / (m + I/r^2) ??
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