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Mathematics 19 Online
OpenStudy (anonymous):

HELP URGENT

OpenStudy (anonymous):

where's the fire?

OpenStudy (anonymous):

give me a sec

OpenStudy (anonymous):

OpenStudy (anonymous):

I have 19 minutes!

OpenStudy (anonymous):

@ganeshie8 :(

OpenStudy (anonymous):

@iambatman

OpenStudy (anonymous):

do you still need help

OpenStudy (anonymous):

yes!!

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

i have 7 minutes for this one:(

OpenStudy (anonymous):

So you have to find the inverse?

OpenStudy (anonymous):

got it thanks!!

OpenStudy (anonymous):

thank you all!! :D

OpenStudy (anonymous):

Uh.. your welcome haha xD

ganeshie8 (ganeshie8):

\[{f^{-1}}'\left(f(x)\right) = \dfrac{1}{f'(x)}\] \[{f^{-1}}'\left(f(1)\right) = \dfrac{1}{f'(1)}\]

OpenStudy (anonymous):

^ yeah!

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