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Mathematics 12 Online
OpenStudy (anonymous):

w^2-6w+?

OpenStudy (anonymous):

Fill in the blank to make the expression a perfect square.

OpenStudy (anonymous):

Hi Sangya21!

OpenStudy (anonymous):

w^2 + (sum of numbers)w + (product of numbers) = 0 w^2 - 6w + ? = 0 sum = -6 = a+b sum can be (0, -6); (-1, -5); (-2, -4); (-3,-3) as we have to find perfect square, then a = b thus sum = -3 -3 a= -3, b =-3 product = 9 Verification w^2 -6w +9 = 0 w^2 - 3w -3w +9 = 0 w(w -3) -3(w -3) = 0 (w-3)(w-3) = 0 (w-3)^2= 0

OpenStudy (anonymous):

Hi @ColeSales

OpenStudy (anonymous):

Thank you.

OpenStudy (anonymous):

Anytime :)

OpenStudy (agent0smith):

For x^2 + bx + _ to make it a perfect square, divide b by 2, and square it, then put that amount in the blank spot. Eg. x^2 + 8x + _ Divide 8 by 2 which is 4. Square 4 to get 16, so 16 goes in the blank.

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