Question

14

Ariaroseb
Write an equation of the line that passes through the given point and is parallel to the given line.

9. (-1,3); y=2x+2
10. (1,2)/ y= -5x+4
11. (18,2); 3y-x= -12
12. (2, -5); 2y=3x+10

Answer 1

please help

Answer 2

OK use the point-slope formula which is y-y1=m(x-x1)
M is ur slope while x1 is or given x coordinate and y1 is ur y coordinate
Make sense?

Answer 3

not really...

Answer 4

Srry =0 let's do 9 together we have y= 2x+2 so we have slope of 2 and y-intercept of 2
Y=MX+b r u familiar with this formula?

Answer 5

yeah

Answer 6

Great! :) parallel lines have the same slope
Y-y1=m(x-x1) we have (-1,3)
-1 is x coordinate and 3 is y coordinate and we have slope of 2( we don't change the slope cuz parallels have same slope)
So far so good?

Answer 7

yeah I think so :)

Answer 8

Nice then let's use our point-slope formula
y-y1=m(x-x1)
M is ur slope while x1 is or given x coordinate and y1 is ur y coordinate
This will give us
Y-3= 2(x-(-1)
Y-3= 2x +2 then adid 3 to bother side and tell me what u get :)

Answer 9

Y-3=2x+5...? That's probably not right but I tried my best

Answer 10

U r doing it right but if u add 3 to both side it will be like this --> y-3+3=2x+2+3
-3+3 is 0 got it ?

Answer 11

yeah

Answer 12

So our equation for #9 is y=2x+5 can u try that rest? Tag me if u get stuck :)

Answer 13

Thank you

Answer 14

My pleasure! :D thanks for the medal

Answer 15

@mathmate & @ariaroseb thanks for the medal ^_^

Answer 16

and a well-deserved one too! :)

Answer 17

Thanks:))