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Let A = {3, 4, 5} and B = {4, 5, 6, 12} and let S be the “divides” relation. That is, for all (x, y) ∈ A × B, x S y <-> x|y. State explicitly which ordered pairs are in S
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3 divides 6, so certainly the order pair (3,6) will be in S. Can you name another one?
3,12?
right. another one?
s={(3,6),(3,12),(4,4),(4,12),(5,)}
OK I got it 3,6-3,12-4,4-4,12-5,5? is that correct
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right. but put them in parenthesis since they are ordered pairs
correction (5,5)
yep typing fast thanks guys I just found this web page #Awesome
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