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I don't really understand how to get the answer to this question, my guess is the square root of 2, but I'm not sure. Please help. If f(x)=1-x, which value is equivalent to the absolute value of f(i)? Possible answers: 0, 1, sqrt of 2, or sqrt of -1.
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@GodGirl360 what is i here?
i is sqrt of -1.
ok.. so f(i)=1-i there fire |f(i)|=sq root(1^2+(-1)^2)=sq root 2
@GodGirl360
Ok, so my first guess was right?
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formula |a+ib|=square root(a^2+b^2).
where a and b are real numbers.
@GodGirl360
yes it is right but there is no place of guess in maths.:)
Ok, thank you so much.:)
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