A particle performing SHM takes time equal to T(time period of SHM) in consecutive appearances at a particular point.This point is :-

A) EXTREME POSITION
B) MEAN POSITION
C) Between positive extreme and mean position
D) Between negative extreme and mean position

Question

A particle performing SHM takes time equal to T(time period of SHM) in consecutive appearances at a particular point.This point is :-

A) EXTREME POSITION
B) MEAN POSITION
C) Between positive extreme and mean position
D) Between negative extreme and mean position

anonymous · Answer

@Pompeii00

anonymous · Answer

(a) Extreme Position i believe

anonymous · Answer

how ?

anonymous · Answer

It would pass the mean position at the bottom of it's oscillation i suppose.. i've never used these terms before so i'm not sure what they're referring to.

anonymous · Answer

extreme sounds like the max potential energies. turning points.

anonymous · Answer

i think answer would be mean position

anonymous · Answer

What is that referring to?

anonymous · Answer

Okay, so I read online the following:|dw:1417938904294:dw|

anonymous · Answer

I think it would be extreme position. Swinging from one side to the other is the period of the oscillation.

I also found this problem online:
Question 1: If a pendulum takes 4 sec to swing in each direction, find the length of the pendulum.

They then go on to define T= 4 s, so it makes me think that's what T is referring to here.

anonymous · Answer

|dw:1417939228690:dw|