Question

the age of a father is twice the square of his sons age
8 yr hence the age of father willl be 4 yrs more then three times the age of his son
calculate their present age

Answer 1

@hartnn

Answer 2

im gettigf 2x^2 - 3x - 20 = 0

Answer 3

@hartnn

Answer 4

Want r u supposed to solve for?

Answer 5

thier present age

Answer 6

@hartnn

Answer 7

@hartnn

Answer 8

@hartnn

Answer 9

@TheSmartOne

Answer 10

Hmm.. Confusing. @ganeshie8 @mathmate @SolomonZelman @jhonyy9 @paki Any ideas?

Answer 11

2X^2 - 3X - 20 = 0
AB

Answer 12

Let f= father's present age
Let s= son's present age

\[f=2(s)^{2}\]

Eight year hence

\[f+8=2(s)^{2}+8\]

So we now have this equation

\[2(s)^{2}+8=3(s+8)+4\]\[2s ^{2}+8=3s+24+4\]\[2s ^{2}+8=3s+28\]\[2s ^{2}-3s-20=0\] Solve for s using the quadratic formula
\[s=4\]

So son is 4 years old and father is 32 years old.