what's 2y^2-9y+20.25 factored out?

Question

jhannybean · Answer

I would suggest using the completing the square method.

anonymous · Answer

yeah im using that method rn

anonymous · Answer

the original equation was 2y^2=9y-9

jhannybean · Answer

then how did you get 20.25 from that?

jhannybean · Answer

all you have to do there is move the $9y-9$ over to the left.

jhannybean · Answer

So it would look like $$2y^2-9y-9=0$$ instead of $$2y^2 -9y +20.25$$

anonymous · Answer

i moved 9y to the left and i got 2y^2-9y=-9

jhannybean · Answer

Okay and now move the $\-9$ over to the left as well.

anonymous · Answer

then i took half of the b coefficient, squared it and added it to both sides

jhannybean · Answer

Did you also factor out the 2 like this? : $$2\left(y^2-\frac{9}{2}y\right)-9=0$$

jhannybean · Answer

When you factor out the 2, it makes it easier to create a quadratic inside the parenthesis. You are essentially completing the square inside

jhannybean · Answer

Are you understanding what I did?

anonymous · Answer

uhm totally

jhannybean · Answer

Where are you confused first? Let's clarify that.