Question

Can someone please help me!?

Answer 1

Imagine there is a frog with 2 genes on the same chromosome that are linked: a gene for spots or no spots (P or p), and a gene for yellow or blue skin coloring (Y or y). Spots and blue skin are the dominant traits. One parent is heterozygous for both traits, and the other parent is homozygous for no spots and yellow skin. After breeding, the F1 generation is as follows:
Spots and Blue skin: 80
Spots and Yellow skin: 12
No spots and Blue skin: 18
No spots and Yellow skin: 90

Answer 2

A. Which are the recombinant phenotypes?

B. How do you know they are recombinant?

C. What alleles would be on each chromosome of each parent BEFORE crossing over occurs?

D. What is the recombination frequency of the genes? (Equation: recombinant frequency = total number of recombinant offspring /total number of offspring)

Answer 3

ok lemme see here

Answer 4

XD

Answer 5

whats the question

Answer 6

A. Which are the recombinant phenotypes?

B. How do you know they are recombinant?

C. What alleles would be on each chromosome of each parent BEFORE crossing over occurs?

D. What is the recombination frequency of the genes? (Equation: recombinant frequency = total number of recombinant offspring /total number of offspring)

@Albany_Goon

Answer 7

Might you consider posting this in Bio Section or something? :3

Answer 8

It is posted in the bio section. @arabpride

Answer 9

LOLZ I KNOW IKNOW x'DDD i noticed AFTER i answered this but i cudnt go back and look at the question :'D im sorry~

Answer 10

(I'm assuming capitals P and Y are the dominant alleles)

The non-recombinant (parental) offspring are always in higher ratios than the recombinant offspring (because recombination is a lower probability event).

Start by writing the genotypes of the parents the possible gametes these can make:

Heterozygous parent: PpYy

possible gametes: PY, Py, pY, py

No spots, yellow skin: ppyy

possible gametes: py

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So since parent 2 can only produce py, the differences come from the first parent.
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Fill in the genotypes, knowning parent 2 only produces py.

Spots and Blue skin: 80 parental PY py
Spots and Yellow skin: 12 recombinant Py py
No spots and Blue skin: 18 recombinant pY py
No spots and Yellow skin: 90 parental py py

therefore the alleles on each chromosome are


Follow the formula for the recombination frequency:

\(\sf recomb~freq=\dfrac{\#~of~recomb}{Total ~offspring}=\dfrac{12+18}{12+18+80+90}\)

Answer 11

Thank you so much!!!! @aaronq

Answer 12

no prob!