Question

find equation of line through points (4, -5) and (1, -1)
PLEASE HELP FINAL EXAM TOMORROW

Answer 1

first, find the slope
m=y2-y1/x2-x1
m=(-1-(-5))/(1-4)
m=4/-3
then use slope int.form
y-y1=m(x-x1)
y-(-5)=-4/3(x-4)
y+5=-4/3x+16/3
-5(1/3) on both sides Multiply by 1/3 to get a common denominator for 16/3
y=-4/3x+1/3

Answer 2

sorry i was trying to work it out. I'm stuck at y+5=-4/3+16/3

Answer 3

well you multiply negative 4 thirds by negative four and get 16/3
then you have to subtract 5 to get y alone. To do that you have to find a common denominator so you can subtract 5 into 16/3

Answer 4

so look at 5 as a fraction
5/1
so (16/3)-(5/1)

Answer 5

multiply 5 by 1/3
and you have 16/3 minus 12/3
wow I messed up
but the result is 4/3
so actually, y=-4/3x+1/3is wrong
the final answer is y=-4/3x+4/3
sorry about that