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Mathematics 26 Online
OpenStudy (anonymous):

Anyone know how to simplify a log? REALLY NEED HELP, FINAL EXAM TOMORROW

OpenStudy (anonymous):

3log(2x)-1/2logx^4

OpenStudy (anonymous):

Tons of ways to simplify it... it depends on the particular problem. Logs can be expanded in several different ways. 1) log(mn) = log(m) + log(n) 2) log(m/n) = log(m) – log(n) 3) log(mn) = n · log(m) Give it a try with these in mind ^^^

OpenStudy (anonymous):

Here's a link that shows it better since it doens't show up on this website very well http://www.purplemath.com/modules/logrules.htm

OpenStudy (anonymous):

well the answer is log(8x^3)-logx^2 but I don't remember how I got it

OpenStudy (anonymous):

Is the answer you got correct? I got a different result...

OpenStudy (anonymous):

-1/2 * logx^4 becomes -2*logx

OpenStudy (anonymous):

then 3log(2x) becomes 3*(log2 + logx)

OpenStudy (anonymous):

putting the two together you get 3log(2x) - .5logx^4 = 3log2 + 3logx - 2logx

OpenStudy (anonymous):

how did you do it?

OpenStudy (anonymous):

which equals 3log2 + logx

OpenStudy (anonymous):

how did you change them?

OpenStudy (anonymous):

Ok let me draw it out

OpenStudy (anonymous):

|dw:1418012342348:dw| using rule #3 in the link i posted

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