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Physics 13 Online
OpenStudy (anonymous):

A block of mass M hangs in equilibrium. The rope which is fastened to the ceiling has a tension of and makes an angle Θ = 55° with the ceiling. What is M?

OpenStudy (anonymous):

OpenStudy (perl):

what is the tension

OpenStudy (anonymous):

64 N

OpenStudy (perl):

I find it hard to believe that the part of the wire where T2 is , is perfectly level

OpenStudy (perl):

should it be T1 cos 55 + T2 = 0 or T1* cos 55 -T2 = 0 are T1 , T2 vectors or magnitudes. T2 is opposite to T2

OpenStudy (anonymous):

i do too, but i that how it's drawn

OpenStudy (perl):

in the x direction

OpenStudy (anonymous):

T1cos55+T2=0, T1 and T2 are vectors

OpenStudy (perl):

ok then Y direction should be T1 sin 55 + T3 = 0 ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

you are right, sorry

OpenStudy (perl):

if T1 sin 55 + T3 = 0 then T1 sin 55 = -T3 but you wrote T1 sin 55 = T3 sorry to be pedantic :)

OpenStudy (perl):

no problem, the vectors and magnitudes sometimes confuse me

OpenStudy (anonymous):

;)

OpenStudy (perl):

can we find the tension T2

OpenStudy (anonymous):

yes, because T1cos 55°+T2=0

OpenStudy (perl):

oh right, just saw that :)

OpenStudy (perl):

but T1 sin 55 = -T3 however |T1| sin 55 = |T3| this is true as far as the magnitudes are concerned

OpenStudy (anonymous):

yes, maybe it easier just with manitudes

OpenStudy (anonymous):

|T1|*cos55°=|T2| and |T1|*sin55°=|T3|=|weigth(M)|

OpenStudy (anonymous):

|dw:1418017535355:dw|

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