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Mathematics 15 Online
OpenStudy (anonymous):

In the figure, AC//DE, FG//BC and AD:DF:FB=1:2:3. If BE=10, find FG.

OpenStudy (anonymous):

|dw:1418017855118:dw|

ganeshie8 (ganeshie8):

somethign wrong in the wording

ganeshie8 (ganeshie8):

`AD:DF=1:2:3` double check that part

OpenStudy (mathstudent55):

There is something missing from the ratio.

OpenStudy (anonymous):

haha corrected. thanks for reminding me

OpenStudy (mathstudent55):

Is it AD:DF:FB?

OpenStudy (mathstudent55):

Oh I see.

OpenStudy (anonymous):

yup

OpenStudy (mathstudent55):

Numbers in circles represent ratios. Plain numbers are lengths of sides. |dw:1418017792347:dw|

OpenStudy (anonymous):

why FG is not 5?

OpenStudy (mathstudent55):

|dw:1418017930012:dw|

ganeshie8 (ganeshie8):

FG = BC/2 not BE/2

OpenStudy (anonymous):

oh..

OpenStudy (mathstudent55):

FH/BE = DF/(DF + FB)

ganeshie8 (ganeshie8):

maybe find EC and use it

OpenStudy (mathstudent55):

FH/10 = 2/5 FH = 4

OpenStudy (mathstudent55):

|dw:1418018182104:dw|

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