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In the figure, AC//DE, FG//BC and AD:DF:FB=1:2:3. If BE=10, find FG.
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|dw:1418017855118:dw|
somethign wrong in the wording
`AD:DF=1:2:3` double check that part
There is something missing from the ratio.
haha corrected. thanks for reminding me
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Is it AD:DF:FB?
Oh I see.
yup
Numbers in circles represent ratios. Plain numbers are lengths of sides. |dw:1418017792347:dw|
why FG is not 5?
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|dw:1418017930012:dw|
FG = BC/2 not BE/2
oh..
FH/BE = DF/(DF + FB)
maybe find EC and use it
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FH/10 = 2/5 FH = 4
|dw:1418018182104:dw|
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