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(ODE) Doing some sample final exam problems to get me ready for my final in five and a half hours. Prompt posted below.
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\[\frac{y}{\sqrt{4-x^2}}\frac{dy}{dx}=y^2+5\]\[\text{Solve the differential Equation.}\]
I think it's separable, so I'm going to treat it as such and take a shot at it like that.
\[\frac{1}{\sqrt{4-x^2}}\frac{dy}{dx}=\frac{y^2+5}{y}\]
\[\frac{y}{y^2+5}dy=\sqrt{4-x^2}\]
\[u=y^2+5, \ du=2ydy;\]\[\frac{1}{2}\int\limits_{}^{}\frac{1}{u}du=\int\limits_{}^{}\sqrt{4-x^2}dx\]
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\[\frac{1}{2}\ln(y^2+5)=2\int\limits_{}^{}\cos^{2}(\theta)\]
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