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Find the unknown length of the triangle
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more info?
You could you Pethagorean theorem: a^2+ b^2= c^2, c being the hypotenuse
|dw:1418077940573:dw|
\[\frac{ 20 }{ BD } = \frac{ 16 }{ 9 }\] Find BD
\[\frac{ 20 }{ x }= \frac{ 16 }{ 9 } then \frac{ 16x }{ 16 }=\frac{ 180 }{ 16 }\] and then work my way up?
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\[\frac{ 20 }{ x } =\frac{ 16 }{ 9 }\] \[x = \frac{ 20*9 }{ 16 }\]
\[x=11.25?\]
what you wrote was correct. Sorry I got confused and yes you got correct ans
thank you
anytime :)
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