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Mathematics 16 Online
OpenStudy (anonymous):

Find the unknown length of the triangle

OpenStudy (anonymous):

more info?

OpenStudy (anonymous):

You could you Pethagorean theorem: a^2+ b^2= c^2, c being the hypotenuse

OpenStudy (anonymous):

|dw:1418077940573:dw|

OpenStudy (anonymous):

\[\frac{ 20 }{ BD } = \frac{ 16 }{ 9 }\] Find BD

OpenStudy (anonymous):

\[\frac{ 20 }{ x }= \frac{ 16 }{ 9 } then \frac{ 16x }{ 16 }=\frac{ 180 }{ 16 }\] and then work my way up?

OpenStudy (anonymous):

\[\frac{ 20 }{ x } =\frac{ 16 }{ 9 }\] \[x = \frac{ 20*9 }{ 16 }\]

OpenStudy (anonymous):

\[x=11.25?\]

OpenStudy (anonymous):

what you wrote was correct. Sorry I got confused and yes you got correct ans

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

anytime :)

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