Trigonometry, please help. Medal will be given. Find the altitude of an isosceles triangle with a vertex angle (that is, the non-base angle) of 70° and a base of 246. Draw a diagram and find the length of the altitude. 175.7 89.5 86.1
|dw:1418082185674:dw| so first, we know isosceles triangles have 2 congruent angles, since the sum of interior angles of a triangle add to 180, what are the missing angles?
I'm guessing since they're congruent they'd both be 90?
Not quite 3 angles in the triangle those 3 have to add to 180 So lets name them as 'x' for now That means \[\large x + x + 70 = 180\] so x = ?
x would equal 55
Right, so what we have is an isosceles triangle that looks like |dw:1418082993457:dw|
Adding the base and drawing the altitude we want, |dw:1418083052081:dw|
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