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Write the equation of a line in slope intercept form that passes through (2, 4) and (5, 4).
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so far I have the slope which is 0/3 so im guessing it's zero just need help plugging it in to the equation.
Well, we know slope intercept form is \[\large y = mx + b\]right?
So if we know 'm' = slope = 0...we would just have \[\large y = b\] so we take either point...and plug it into this...so lets use (2,4) \[\large 4 = b\] So our equation is \[\large y = 4\] also known as the horizontal line |dw:1418089344691:dw|
i got it thanks!!
No problem :)
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