Question

Using u-sub
-5x/(1-2x^2)^2 dx

Answer 1

let

u = 1- 2x^2

Answer 2

du = -4x dx

Answer 3

so
dx = du / (-4x)

Answer 4

\[-5 \int\limits \frac{ x }{ u }\frac{ du }{ -4x }\]

Answer 5

And I plugged them in in terms of u but then I got confused

Answer 6

Ohhh I didn't factor out the 5

Answer 7

Why isn't it u^2

Answer 8

oh yeah

Answer 9

\[\frac{ 5 }{ 4 } \int\limits u ^{-2}du\]

Answer 10

So it should be u^2?

Answer 11

yeah it is 1 over u^2 or just u^-2 like i wrote... i erased the wrong one and rewrote it

Answer 12

\[\frac{ 5 }{ 4 }*\frac{ -1 }{ u }\]

Answer 13

sub back in u = 1-2x^2