What is the standard form of the equation of the circle in the graph?

(x + 3)2 + (y - 1)2 = 2
(x - 3)2 + (y + 1)2 = 1
(x - 3)2 + (y + 1)2 = 2
(x + 3)2 + (y - 1)2 = 1

Question

What is the standard form of the equation of the circle in the graph?
 	
	(x + 3)2 + (y - 1)2 = 2
	(x - 3)2 + (y + 1)2 = 1
	(x - 3)2 + (y + 1)2 = 2
	(x + 3)2 + (y - 1)2 = 1

saylilbaby · Answer

attachment

saylilbaby · Answer

@Directrix

directrix · Answer

First thing, we need to look at how the standard form of a circle looks and then compare it to the options. Just a sec.

directrix · Answer

Look at the attachment and let's compare that to the options.

Any idea which one it might be?

directrix · Answer

I just saw the circle diagram.  Do you get (-3, 1) for the center?

directrix · Answer

And, with a radius of 1?

directrix · Answer

So, (x - (-3)) ^2 + (y - 1) ^2 = 1^2

(x + 3)^2 + (y - 1) ^2 = 1

@Saylilbaby    Do any of the options look like that?