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Mathematics 10 Online
OpenStudy (anonymous):

The average rate of change from 6 to 7 is ? Given h(x)=x^2-7x

OpenStudy (anonymous):

Let's graph the equation!

OpenStudy (anonymous):

Let's actually look at what the points are at x = 6 and x = 7

OpenStudy (anonymous):

So Solve for h(6) and h(7)

OpenStudy (anonymous):

how to do?

OpenStudy (anonymous):

This will give you the information for two coordinates, one for (6, h(6)) and (7, h(7))

OpenStudy (anonymous):

Ok well, h(6) will be, h(6) = (6)^2 - 7(6) This will show you what the y-value is at x = 6

OpenStudy (anonymous):

We are doing this so that we can see what the graph is at x = 6 and x = 7 so we can find the slope of the line from 6 to 7 and establish what the average rate of change (slope) is from x = 6 to 7. See?

OpenStudy (anonymous):

i think so

OpenStudy (anonymous):

Find h(6), which is -6, this means that at x = 6, y is equal to -6. This gives us the point (6, -6)

OpenStudy (anonymous):

Do the same for h(7) for me, and let me know what you get. You are doing this to see what "y" is when x = 7, that is what h(7) means in; h(x) = x^ - 7x

OpenStudy (anonymous):

so isnt h give us the poin (7,-7)?

OpenStudy (anonymous):

Then you will have a second coordinate, where x = 7. Find the slope from the first coordinate (6, -6) to the new one,|dw:1418120074713:dw|

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