solve the system of equations by substitution. what is the solution for x
2x + y = 1
4x + 2y = -1
A. x = 0
B. x = 2
C. there is no x value as there is no solution
D. x can be any value as there are an infinite number of solutions
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OpenStudy (freckles):
you can try to solve by elimination and see what happens
multiply the first equation by -2 and then add the equations together afterwards
OpenStudy (freckles):
what did you when you multiply the first equation by -2?
OpenStudy (tatianagarcia90300):
y is equal to -2
OpenStudy (freckles):
I think you should try again,
OpenStudy (freckles):
multiply the first equation by -2
so -2(2x+y=1)
is -4x-2y=-2
now add the following equations:
-4x-2y=-2
4x+2y=-1
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OpenStudy (freckles):
add the first column -4x+4x
add the second column -2y+2y
=
add the third column -2+(-1)
OpenStudy (tatianagarcia90300):
x + y = -3
OpenStudy (freckles):
something+(-same something)=0
OpenStudy (tatianagarcia90300):
so no solution
OpenStudy (freckles):
-x+x=0
x+(-x)=0
yes
because we have
first column=0
second column=0
=
third column =-3
0+0=-3 <--not a true equation
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