solve the system of equations by substitution. what is the solution for x 2x + y = 1 4x + 2y = -1 A. x = 0 B. x = 2 C. there is no x value as there is no solution D. x can be any value as there are an infinite number of solutions
you can try to solve by elimination and see what happens multiply the first equation by -2 and then add the equations together afterwards
what did you when you multiply the first equation by -2?
y is equal to -2
I think you should try again,
multiply the first equation by -2 so -2(2x+y=1) is -4x-2y=-2 now add the following equations: -4x-2y=-2 4x+2y=-1 =============
add the first column -4x+4x add the second column -2y+2y = add the third column -2+(-1)
x + y = -3
something+(-same something)=0
so no solution
-x+x=0 x+(-x)=0 yes because we have first column=0 second column=0 = third column =-3 0+0=-3 <--not a true equation
oh ok i get it thank you so much
np
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