Question

@myininaya
Need help with solving unknown variables using quadratic trigonometry. Question is in attached file.

Answer 1

hey are you still here?

Answer 2

So we have the following equations:
\[\cot^2(\frac{\pi}{6})-b \cot(\frac{\pi}{6})+c=0 \\ \cot^2(\frac{\pi}{4})- b \cot(\frac{\pi}{4})+c=0 \\ \cot^2(\frac{7 \pi}{6})-b \cot(\frac{7 \pi }{6})+c=0 \\ \cot^2(\frac{5\pi}{4})-b \cot(\frac{5\pi}{4})+c=0\]
I'm pretty sure this is more equations than we need
but whatever
let's just look at the first two equations

Answer 3

you need to first evaluate cot(pi/6) or cot(pi/4)

Answer 4

i mean both

Answer 5

you will have a system of equations to solve

Answer 6

\[(\sqrt{3})^2-b(\sqrt{3})+c=0 \\ 1-b+c=0\]