5x+3y=2x+8
what do you have to do?
solve for x
ok so you wanna get x by itself on the left side of the equation. to do that, we first have to get rid of 3y. how should we do that?
subtract it from the left side
i think u are right so far i ant ood at math sooo
well, you subtract it from both sides. so now we have 5x = 2x - 3y + 8 now we have to get rid of the 2x on the right. how do we do that?
-3x= -8+3y = x= 8/3 +y
wouldnt you combine like terms and get 7x?
no, you would also have to subtract it from both sides after you do that, you'd get 3x = -3y + 8
we don't 3x, we just want x. so we're going to divide both sides by 3
we don't want 3x*
wouldnt it come out as -8/3
i mean positive
3x = -3y + 8 x = -y + 8/3
so you divide both by -1 and get x=-8/3?
we can't actually solve for x. we can only solve for x in terms of y x = -y + 8/3 is as close an answer you get without knowing what y is
okay thank you
no problemo :)
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