4(x+8)^2=144 to standard form,
standard form is ax^2 + bx + c,

i got 4x^2+64x+112, is this right

Question

4(x+8)^2=144 to standard form,
standard form is ax^2 + bx + c,

i got 4x^2+64x+112, is this right

catlover5925 · Answer

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catlover5925 · Answer

does this make sense??? do you have answer choices??

catlover5925 · Answer

@iambatman am i doing this right??

anonymous · Answer

Yes, you're doing it right :)

catlover5925 · Answer

thanks

catlover5925 · Answer

do you understand what i did @anom123

anonymous · Answer

I understand what you did, but isn't there more to it? I'm trying to find the X's by using x=-b sqrt(-b^2 - 4ac) / 2
So y has to be 0, so i subtracted 114 on the right side to get 4x^2+64x+112

@iambatman @Catlover5925

anonymous · Answer

That's if you're finding the roots ( the solutions) and you're using the quadratic formula. From your question is just asks to turn it into standard form. But, you can use the quadratic formula to find the x's if you like. 

If there is a y and x value and you're setting something = 0, means you're looking for the intercepts.

Hope this helps.

anonymous · Answer

thank you very much!@

catlover5925 · Answer

no problem ^.^