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a line passes through the point (-6,3) and has a slope of 5/2. write an equation in slope intercept form for this line
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\[y-3=\frac{5}{2}(x+6)\] solve for \(y\)
How do i do that
distribute on the right first then add 3
\[y-3=\frac{5}{2}x+15\] is the first step
y = 5/2x + 18
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yeah
thats the equation
yes
slope intercept form is Y = Mx + B M is slope and B is the y-intercept therfore the equation is Y = 5/2x + 3
except the 3 is an 18
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@satellite73 i dont think that is correct because slope intercet for is Y = mx + b M the slope is 5/2 b = 3 why is the 3 an 18?? you take the y from the point she gave
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