Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

in 25 is the power to which ____ must be raised in order to produce a value of 25

OpenStudy (anonymous):

OpenStudy (anonymous):

@triciaal @sourwing @satellite73

OpenStudy (anonymous):

5 squared is 25, if that is what you're asking

OpenStudy (anonymous):

what is it?

OpenStudy (anonymous):

it said which __(blank) must be raised to produce a value of 25?

OpenStudy (anonymous):

what goes into the blank?

OpenStudy (anonymous):

Whatever numeral would be raised

OpenStudy (anonymous):

basically the question is asking you what number can be raised to an exponent to get 25

OpenStudy (anonymous):

so it could be 5^2

OpenStudy (anonymous):

lets read it carefully

OpenStudy (anonymous):

it says \[\ln(25)\] is the number to which _____ must be raised to get 25

OpenStudy (anonymous):

they are asking you if you know what the base of the natural log is that base it the transcendental number \(e\)

OpenStudy (anonymous):

your answer to this question is "\(e\)"

OpenStudy (anonymous):

so is just e

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

OpenStudy (anonymous):

I got B

OpenStudy (anonymous):

@satellite73?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

OpenStudy (anonymous):

C right, @satellite73?

OpenStudy (anonymous):

@triciaal @Mertsj

OpenStudy (mertsj):

\[\sqrt[25]25\]

OpenStudy (mertsj):

Because: \[(\sqrt[25]{25})^{25}=25\]

OpenStudy (anonymous):

I got C

OpenStudy (mertsj):

What is the base?

OpenStudy (triciaal):

too many question here !!!!

OpenStudy (triciaal):

review to subtract logs divide the numbers to add logs multiply the numbers number in front of the log is the exponent of the number log is the number to which the base must be raised to get that number

OpenStudy (anonymous):

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!