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Mathematics 14 Online
OpenStudy (anonymous):

fan + medal picture below

OpenStudy (anonymous):

OpenStudy (anonymous):

click help

OpenStudy (anonymous):

that does nothing lol

OpenStudy (anonymous):

~_~

Directrix (directrix):

The probability that the dart hits the shaded area of the target is the area of the shaded region divided by the area of the entire target. The area of the shaded circle is A = pi * r^2 so the area of the shaded region is pi* 6^2 or 36 pi. The area of the entire target is, by the same formula A = pi * 13^2 = 169*pi. Probability of hitting the shaded region is(36*pi) /(169*pi) . See if you can simplify that @heythatsness

OpenStudy (anonymous):

113.04 / 530.66 ?

OpenStudy (anonymous):

flip the order though

Directrix (directrix):

Why?

OpenStudy (anonymous):

you divide by the larger number?

Directrix (directrix):

I did ( 36*pi) /(169*pi) = 36 / 169 = .21 to the nearest hundredth. The pi factors divided out.

Directrix (directrix):

That is what 113.04 / 530.66 equals when you divide. http://www.wolframalpha.com/input/?i=113.04+%2F+530.66+

Directrix (directrix):

So, roughly 21 out of every 100 randomly tossed darts that hit the target will hit the shaded region.

OpenStudy (anonymous):

thats what i got

Directrix (directrix):

Yes, we are in agreement on the answer.

OpenStudy (anonymous):

thank you for helping!

Directrix (directrix):

You are welcome.

OpenStudy (anonymous):

I did!

Directrix (directrix):

Thank you.

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