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HELP solve for x? 3/(x-3)=x/(x-3)-3/2 and is it extraneous or non extraneous?
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what are you trying to solve ???
@TrapBoiTrynaEducaate I edited it
3/(x-3) - x/(x-3) = - 3/2 (3 - x) / (x - 3) = - 3/2 3 - x = -3/2 (x-3) 3 - x = -(3/2)x + 9/2 6 - 2x = -3x + 9 x = 3
@TrapBoiTrynaEducaate is the solution extraneous or non extraneous?
idek i just did it like that
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try plugging in x = 3 into original equation
@TrapBoiTrynaEducaate if you plug in x=3 you get 0 in the denominator, so I guess it's extraneous?
yup
right
@cwrw238 thank you
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yw
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