(5xy^2 + 3x^2y - 2y^2) - ( -7x^2y - 6xy^2 + y^2) simplify
@SolomonZelman
\(\large\color{black}{ (5xy^2 + 3x^2y - 2y^2)- ( -7x^2y - 6xy^2 + y^2) }\)
lets do this, \(\large\color{black}{ 5xy^2 + 3x^2y - 2y^2- ( -7x^2y) - (-6xy^2) -( y^2) }\) . Do you agree with what I have done here?
Yes
So, now simplify the parts I"ll label in red. \(\large\color{black}{ 5xy^2 + 3x^2y - 2y^2\color{red}{- -}7x^2y \color{red}{- -}6xy^2 \color{black}{- }y^2 }\).
the 2 negatives, become what? (re-write the equation, now)
positive
yes, so it becomes, \(\large\color{black}{ 5xy^2 + 3x^2y - 2y^2\color{red}{+}7x^2y \color{red}{+}6xy^2 \color{black}{- }y^2 }\)
Then combine like terms
And then, the like terms, are \(\large\color{black}{ \color{blue}{5xy^2} \color{red}{+ 3x^2y} \color{green}{- 2y^2} \color{red}{+7x^2y} \color{blue}{+6xy^2} \color{green}{-y^2} }\)
Sorry it took long to color them.
11xy^2 + 10x^2y + 2y^2?
\(\large\color{black}{ \color{blue}{11xy^2} \color{red}{+ 10x^2y} \color{green}{- 2y^2} \color{green}{-y^2} }\)
one term has an incorrect coefficient.
\(\large\color{black}{ \color{green}{- 2y^2} \color{green}{-y^2} \ne2y^2}\) right?
Yes didnt i have that
you said that the ;ast term is +2y^2, when it is -3y^2.
smiley2015 your hot
Join our real-time social learning platform and learn together with your friends!