hey guys what how do u answer this a+b+6=a+c
ill give you a medal if u get it
1) Are you sure the question says \(\large\color{black}{a+b+6=a+c }\) ? 2) What are you exactly asked to do?
im helping someone on here
There are three consecutive integers. The product of the smaller two integers added to 6 is equal to the product of the smallest and largest integer. What is the largest integer?
thats the question
`There are three consecutive integers.` \(\large\color{black}{(x-1)+x+(x+1) }\) (where x is the middle number.) ``` The product of the smaller two integers added to 6 is equal to the product of the smallest and largest integer. ``` \(\large\color{black}{(x-1)x+6=(x-1)(x+1) }\) Solve this equation.
ok
x=7
is that right
``` (x-1)x+6=(x-1)(x+1) x^2-x+6=x^2-1 -x+6=-7 -x=-7 x=7 ```
x is the middle number, so the largest number, the x+1, is 8.
cool thanks
Anytime!
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