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OpenStudy (anonymous):
find the value of x. The diagram is not drawn to scale.
(I know how to solve the equation, i have trouble with how to set the equation up)
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OpenStudy (anonymous):
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (triciaal):
hint; what is the sum of all the angles in a quadrilateral?
jimthompson5910 (jim_thompson5910):
this is a pentagon
OpenStudy (triciaal):
sorry
what is the sum of the angles in the pentagon?
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OpenStudy (anonymous):
540 Degrees?
OpenStudy (triciaal):
measure of each interior angle of a regular n-gon 1/n(n-2)*180
measure of each exterior angle of a regular n-gon 1/n*360
OpenStudy (anonymous):
Oh i got it!
You would end up having 260+3x+10=540
and in the end my answer is x=90
jimthompson5910 (jim_thompson5910):
I think you're missing a few terms when you got 260+3x+10=540
OpenStudy (anonymous):
I am not sure how, i combined 148 and 112 and got 260. How would you solve it? Did you come up with another answer?
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jimthompson5910 (jim_thompson5910):
you missed the 90 degree angle (the square marked angle)
jimthompson5910 (jim_thompson5910):
also, don't leave out the 3x+10 and x degree angles
OpenStudy (anonymous):
ok i am lost now.
OpenStudy (zarkon):
you have 5 angles to add up. looks like you only added 3 of them
jimthompson5910 (jim_thompson5910):
|dw:1418273898903:dw|
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jimthompson5910 (jim_thompson5910):
I think you only considered these 3 angles
|dw:1418273991292:dw|
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